提交 e2d7452c 作者: imClumsyPanda

update chinese_text_splitter.py

上级 3111fb56
......@@ -103,7 +103,8 @@ def similarity_search_with_score_by_vector(
doc.page_content += doc0.page_content
if not isinstance(doc, Document):
raise ValueError(f"Could not find document for id {_id}, got {doc}")
docs.append((doc, scores[0][j]))
doc_score = min([scores[0][id] for id in [indices[0].tolist().index(i) for i in id_seq if i in indices[0]]])
docs.append((doc, doc_score))
torch_gc()
return docs
......
......@@ -50,6 +50,9 @@ PROMPT_TEMPLATE = """已知信息:
根据上述已知信息,简洁和专业的来回答用户的问题。如果无法从中得到答案,请说 “根据已知信息无法回答该问题” 或 “没有提供足够的相关信息”,不允许在答案中添加编造成分,答案请使用中文。 问题是:{question}"""
# 文本分句长度
SENTENCE_SIZE = 100
# 匹配后单段上下文长度
CHUNK_SIZE = 250
......
from langchain.text_splitter import CharacterTextSplitter
import re
from typing import List
from configs.model_config import SENTENCE_SIZE
class ChineseTextSplitter(CharacterTextSplitter):
def __init__(self, pdf: bool = False, **kwargs):
super().__init__(**kwargs)
self.pdf = pdf
def split_text(self, text: str) -> List[str]:
def split_text1(self, text: str) -> List[str]:
if self.pdf:
text = re.sub(r"\n{3,}", "\n", text)
text = re.sub('\s', ' ', text)
text = text.replace("\n\n", "")
sent_sep_pattern = re.compile('([﹒﹔﹖﹗.。!?]["’”」』]{0,2}|(?=["‘“「『]{1,2}|$))') # del :;
sent_sep_pattern = re.compile('([﹒﹔﹖﹗.。!?]["’”」』]{0,2}|(?=["‘“「『]{1,2}|$))') # del :;
sent_list = []
for ele in sent_sep_pattern.split(text):
if sent_sep_pattern.match(ele) and sent_list:
......@@ -22,4 +22,37 @@ class ChineseTextSplitter(CharacterTextSplitter):
sent_list.append(ele)
return sent_list
def split_text(self, text: str) -> List[str]:
if self.pdf:
text = re.sub(r"\n{3,}", r"\n", text)
text = re.sub('\s', " ", text)
text = re.sub("\n\n", "", text)
text = re.sub(r'([;;.!?。!?\?])([^”’])', r"\1\n\2", text) # 单字符断句符
text = re.sub(r'(\.{6})([^"’”」』])', r"\1\n\2", text) # 英文省略号
text = re.sub(r'(\…{2})([^"’”」』])', r"\1\n\2", text) # 中文省略号
text = re.sub(r'([;;!?。!?\?]["’”」』]{0,2})([^;;!?,。!?\?])', r'\1\n\2', text)
# 如果双引号前有终止符,那么双引号才是句子的终点,把分句符\n放到双引号后,注意前面的几句都小心保留了双引号
text = text.rstrip() # 段尾如果有多余的\n就去掉它
# 很多规则中会考虑分号;,但是这里我把它忽略不计,破折号、英文双引号等同样忽略,需要的再做些简单调整即可。
ls = [i for i in text.split("\n") if i]
for ele in ls:
if len(ele) > SENTENCE_SIZE:
ele1 = re.sub(r'([,,.]["’”」』]{0,2})([^,,.])', r'\1\n\2', ele)
ele1_ls = ele1.split("\n")
for ele_ele1 in ele1_ls:
if len(ele_ele1) > SENTENCE_SIZE:
ele_ele2 = re.sub(r'([\n]{1,}| {2,}["’”」』]{0,2})([^\s])', r'\1\n\2', ele_ele1)
ele2_ls = ele_ele2.split("\n")
for ele_ele2 in ele2_ls:
if len(ele_ele2) > SENTENCE_SIZE:
ele_ele3 = re.sub('( ["’”」』]{0,2})([^ ])', r'\1\n\2', ele_ele2)
ele2_id = ele2_ls.index(ele_ele2)
ele2_ls = ele2_ls[:ele2_id] + [i for i in ele_ele3.split("\n") if i] + ele2_ls[ele2_id + 1:]
ele_id = ele1_ls.index(ele_ele1)
ele1_ls = ele1_ls[:ele_id] + [i for i in ele2_ls if i] + ele1_ls[ele_id + 1:]
id = ls.index(ele)
ls = ls[:id] + [i for i in ele1_ls if i] + ls[id+1:]
return ls
......@@ -15,8 +15,8 @@ def get_vs_list():
lst = os.listdir(VS_ROOT_PATH)
if not lst:
return lst_default
lst.sort(reverse=True)
return lst + lst_default
lst.sort()
return lst_default + lst
vs_list = get_vs_list()
......
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